0=-16x^2+15x+18

Solution for 0=-16x^2+15x+18 equation:

0=-16x^2+15x+18

We move all terms to the left:

0-(-16x^2+15x+18)=0

We add all the numbers together, and all the variables

-(-16x^2+15x+18)=0

We get rid of parentheses

16x^2-15x-18=0

a = 16; b = -15; c = -18;
Δ = b2-4ac
Δ = -152-4·16·(-18)
Δ = 1377
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1377}=\sqrt{81*17}=\sqrt{81}*\sqrt{17}=9\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-9\sqrt{17}}{2*16}=\frac{15-9\sqrt{17}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+9\sqrt{17}}{2*16}=\frac{15+9\sqrt{17}}{32}
$